std::ranges::rbegin
| Defined in header <ranges>
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| inline namespace /*unspecified*/ { inline constexpr /*unspecified*/ rbegin = /*unspecified*/; |
(since C++20) (customization point object) |
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| Call signature |
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| template< class T > requires /* see below */ |
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Returns an iterator to the last element of the argument.
Let t be an object of type T. If the argument is an lvalue or ranges::enable_borrowed_range<std::remove_cv_t<T>> is true, then a call to ranges::rbegin is expression-equivalent to:
- std::forward<T>(t).rbegin(), if that expression is valid, and its return type models
std::input_or_output_iterator. - Otherwise, rbegin(std::forward<T>(t)), if
Tis a class or enumeration type, the aforementioned unqualified call is valid, its return type modelsstd::input_or_output_iterator, where the overload resolution is performed with the following candidates:- void rbegin(auto&) = delete;
- void rbegin(const auto&) = delete;
- any declarations of
beginfound by argument-dependent lookup.
- Otherwise, std::make_reverse_iterator(ranges::end(std::forward<T>)) if both ranges::begin(std::forward<T>(t)) and ranges::end(std::forward<T>(t)) are valid expressions, have the same type, and that type models
std::bidirectional_iterator.
In all other cases, a call to ranges::rbegin is ill-formed, which can result in substitution failure when ranges::rbegin(t) appears in the immediate context of a template instantiation.
Expression-equivalent
Expression e is expression-equivalent to expression f, if e and f have the same effects, either are both potentially-throwing or are both not potentially-throwing (i.e. noexcept(e) == noexcept(f)), and either are both constant subexpressions or are both not constant subexpressions.
Customization point objects
The name ranges::rbegin denotes a customization point object, which is a const function object of a literal semiregular class type (denoted, for exposition purposes, as rbegin_ftor). All instances of rbegin_ftor are equal. Thus, ranges::rbegin can be copied freely and its copies can be used interchangeably.
Given a set of types Args..., if std::declval<Args>()... meet the requirements for arguments to ranges::rbegin above, rbegin_ftor will satisfy std::invocable<const rbegin_ftor&, Args...>. Otherwise, no function call operator of rbegin_ftor participates in overload resolution.
Notes
If the argument is an rvalue (i.e. T is an object type) and ranges::enable_borrowed_range<std::remove_cv_t<T>> is false, the call to ranges::rbegin is ill-formed, which also results in substitution failure.
The return type models std::input_or_output_iterator in all cases.
Example
#include <iostream> #include <vector> #include <ranges> int main() { std::vector<int> v = { 3, 1, 4 }; auto vi = std::ranges::rbegin(v); std::cout << *vi << '\n'; *vi = 42; // OK int a[] = { -5, 10, 15 }; auto ai = std::ranges::rbegin(a); std::cout << *ai << '\n'; *ai = 42; // OK }
Output:
4 15
See also
| (C++20) |
returns a reverse iterator to a read-only range (customization point object) |
| (C++14) |
returns a reverse iterator to a container or array (function template) |