std::vector<T,Allocator>::begin, std::vector<T,Allocator>::cbegin
From cppreference.com
| iterator begin(); |
(until C++11) | |
| iterator begin() noexcept; |
(since C++11) (until C++20) |
|
| constexpr iterator begin() noexcept; |
(since C++20) | |
| const_iterator begin() const; |
(until C++11) | |
| const_iterator begin() const noexcept; |
(since C++11) (until C++20) |
|
| constexpr const_iterator begin() const noexcept; |
(since C++20) | |
| const_iterator cbegin() const noexcept; |
(since C++11) (until C++20) |
|
| constexpr const_iterator cbegin() const noexcept; |
(since C++20) | |
Returns an iterator to the first element of the vector.
If the vector is empty, the returned iterator will be equal to end().
Parameters
(none)
Return value
Iterator to the first element.
Complexity
Constant.
Example
Run this code
#include <algorithm> #include <iostream> #include <numeric> #include <string> #include <vector> int main() { std::vector<int> nums {1, 2, 4, 8, 16}; std::vector<std::string> fruits {"orange", "apple", "raspberry"}; std::vector<char> empty; // Print vector. std::for_each(nums.begin(), nums.end(), [](const int n) { std::cout << n << ' '; }); std::cout << '\n'; // Sums all integers in the vector nums (if any), printing only the result. std::cout << "Sum of nums: " << std::accumulate(nums.begin(), nums.end(), 0) << '\n'; // Prints the first fruit in the vector fruits, checking if there is any. if (!fruits.empty()) std::cout << "First fruit: " << *fruits.begin() << '\n'; if (empty.begin() == empty.end()) std::cout << "vector 'empty' is indeed empty.\n"; }
Output:
1 2 4 8 16 Sum of nums: 31 First fruit: orange vector 'empty' is indeed empty.
See also
| (C++11) |
returns an iterator to the end (public member function) |